小恐龙の得分秘籍

前几天看到有群友在群里晒他玩 chrome://dino/的战绩，我微微一笑：

法一：让小恐龙自动浪

先上代码

function TrexRunnerBot() {
 
  const makeKeyArgs = (keyCode) => {
    const preventDefault = () => void 0;
    return {keyCode, preventDefault};
  };
 
  const upKeyArgs = makeKeyArgs(38);
  const downKeyArgs = makeKeyArgs(40);
  const startArgs = makeKeyArgs(32);
 
  if (!Runner().playing) {
    Runner().onKeyDown(startArgs);
    setTimeout(() => {
      Runner().onKeyUp(startArgs);
    }, 500);
  }
 
  function conquerTheGame() {
    if (!Runner || !Runner().horizon.obstacles[0]) return;
 
    const obstacle = Runner().horizon.obstacles[0];
 
    if (obstacle.typeConfig && obstacle.typeConfig.type === 'SNACK') return;
 
    if (needsToTackle(obstacle) && closeEnoughToTackle(obstacle)) tackle(obstacle);
  }
 
  function needsToTackle(obstacle) {
    return obstacle.yPos !== 50;
  }
 
  function closeEnoughToTackle(obstacle) {
    return obstacle.xPos <= Runner().currentSpeed * 18;
  }
 
  function tackle(obstacle) {
    if (isDuckable(obstacle)) {
      duck();
    } else {
      jumpOver(obstacle);
    }
  }
 
  function isDuckable(obstacle) {
    return obstacle.yPos === 50;
  }
 
  function duck() {
    Runner().onKeyDown(downKeyArgs);
 
    setTimeout(() => {
      Runner().onKeyUp(downKeyArgs);
    }, 500);
  }
 
  function jumpOver(obstacle) {
    if (isNextObstacleCloseTo(obstacle))
      jumpFast();
    else
      Runner().onKeyDown(upKeyArgs);
  }
 
  function isNextObstacleCloseTo(currentObstacle) {
    const nextObstacle = Runner().horizon.obstacles[1];
 
    return nextObstacle && nextObstacle.xPos - currentObstacle.xPos <= Runner().currentSpeed * 42;
  }
 
  function jumpFast() {
    Runner().onKeyDown(upKeyArgs);
    Runner().onKeyUp(upKeyArgs);
  }
 
  return {conquerTheGame: conquerTheGame};
}
 
let bot = TrexRunnerBot();
let botInterval = setInterval(bot.conquerTheGame, 2);

复制便捷版

function TrexRunnerBot(){function f(){Runner().onKeyDown(d);setTimeout(function(){Runner().onKeyUp(d)},500)}var b=function(a){return{keyCode:a,preventDefault:function(){}}},c=b(38),d=b(40),e=b(32);Runner().playing||(Runner().onKeyDown(e),setTimeout(function(){Runner().onKeyUp(e)},500));return{conquerTheGame:function(){if(Runner&&Runner().horizon.obstacles[0]){var a=Runner().horizon.obstacles[0];if((!a.typeConfig||"SNACK"!==a.typeConfig.type)&&50!==a.yPos&&a.xPos<=18*Runner().currentSpeed)if(50=== a.yPos)f();else{var b=Runner().horizon.obstacles[1];if(b&&b.xPos-a.xPos<=42*Runner().currentSpeed)Runner().onKeyDown(c),Runner().onKeyUp(c);else Runner().onKeyDown(c)}}}}}var bot=TrexRunnerBot(),botInterval=setInterval(bot.conquerTheGame,2);

法二：在分数上动点手脚

代码拿走

let hackScore = 0;

Object.defineProperty(Runner.instance_, 'distanceRan', {
  get: () => hackScore,
  set: (value) => hackScore = value + Math.floor(Math.random() * 1000),//1000是分数的倍数
  configurable: true,
  enumerable: true,
});

复制便捷版

var hackScore=0;Object.defineProperty(Runner.instance_,"distanceRan",{get:function(){return hackScore},set:function(a){return hackScore=a+Math.floor(1E3*Math.random())},configurable:!0,enumerable:!0});

将上面代码执行之后，再次运行程序，你会发现你获取分数的速度提升了一千倍。

如果你将第一个方案和这个方案的代码结合，会获得一个能够自动奔跑获得高分的“智能小恐龙”。

不过因为我们的“外挂”是基于计时器进行距离计算并模拟用户操作的，当你获得很高很高的分数之后，障碍物推进速度过快，一旦你进行窗口的来回切换，游戏进行暂停和游玩的状态切换，很大概率上“外挂”操作会延时，导致 GAME OVER。

如何能避免这个事情呢，我们来讲讲第三个套路。